Question

find b given that:
A(4,10) and B(b,7) are 5 units apart.

How can i solve it ?

Answer 1

distance formula\[5=\sqrt(4-b)^2+(10-7)^2\]
that sqrt should be over the whole right side

Answer 2

then solve for b

Answer 3

b=8 or b=0
there are 2 possibilities.

Answer 4

So it would be
5 = 4-b + 9?

Answer 5

could you show how you got your results?

Answer 6

please cause i have 4 problems like this

Answer 7

the (4-b) is still square and the right side should still be under the sqrt

Answer 8

yeah

Answer 9

\[5=\sqrt((4-b)^2+(10-7)^2)\]
\[25=(4-b)^2+9\]
subtract 9\[16=(4-b)^2\]
take the squareroot, and remember that when taking the squareroot you have to use the negative and positive\[\pm4=4-b\]

Answer 10

can you complete from there? or want me to finish?

Answer 11

finish it please

Answer 12

sorry! im just a better learning seeing it out solved

Answer 13

so you have\[4=4-b \]
subtract 4 and multiply by -1 to get rid of the negative
\[0=b\]
and you also have\[-4=4-b\]
subtract 4\[-8=-b\] and multiply by -1 to get rid of the negative
\[8=b\]

Answer 14

I don't mind. Everyone learns differently and I'm happy to help.

Answer 15

thank you but i have one more

Answer 16

the question is

Answer 17

A(b,b) is sqrt(18) units from its origin.

Answer 18

find b

Answer 19

the origin is at (0,0) so assuming the b is the same you have\[\sqrt18=\sqrt{(b-0)^2+(b-0)^2}\]

Answer 20

so\[\sqrt{18}=\sqrt{b^2+b^2}\]
\[\sqrt{18}=\sqrt{2b^2}\]square both sides
\[18=2b^2\]divide by 2
\[9=b^2\]take the square \[\pm3=b\]root