1/64m^3+n^3
Factor the following expression
please please help (it my last set of prob. on my hw)
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OpenStudy (anonymous):
you have the sum of two cubes 1/4 m and n are the two cubes. Do you know the formula for sum of cubes?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]
and in this case a=1/4m and b=n
OpenStudy (anonymous):
1/4m or 1/64?? i am not seeing where u get 1/4??
OpenStudy (anonymous):
the cube root of 1/64 is 1/4 \[(1/4)^3 = 1/64\]
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OpenStudy (anonymous):
oh ok sorry i get it
OpenStudy (anonymous):
if you type your answer, I will let you know if you are correct!
OpenStudy (anonymous):
1/4^3+n^2=(1/4^3+n)(1/4^2+1/4n+n^2)
OpenStudy (anonymous):
what happened to m :(
(1/4 m+n)(1/16 m^2-1/4mn+n^2)
a=1/4 m b=n
a^2 = 1/16m^2
ab = 1/4 mn
b^2 = n^2
OpenStudy (anonymous):
thanks. I realize my mistake when i see them so that is good. I am in a struggle with this math class this sem. I keep frogeting simple things.Thanks for your help.
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OpenStudy (anonymous):
practice and you will get better!!!! Smart choice choosing to come here!