Question

(x^2-25/x^2-6x+5)(x^2-1/x^2-2x+1)= x+5/x-2 please explain cuz I got something a lil different

Answer 1

Each of these factor, so we have:
\[(x-5)(x+5)/(x-1)(x-5) * (x-1)(x+1)/(x-1)(x-1)\]
the (x-5)'s cancel out on the first one, and the (x-1)'s cancel out on the 2nd one

Answer 2

\[((x - 5)(x +5))/((x - 5)(x+1)) = (x + 5)/(x + 1)\]
\[((x + 1)(x-1))/(x - 1)(x -1)) = (x+1)/(x-1)\]

(x + 10 will cancel leaving (x+5)/(x-1)

Answer 3

\[(x^2-25)(x^2-1)=(x+5)(x-5)(x-1)(x+1)\]
\[(x^2-6x+5)(x^2-2x+1)=(x-5)(x-1)(x-1)(x-1)\]

Answer 4

so we have
\[(x+5)/(x-1) * (x+1)/(x-1)\]

Answer 5

@campbell you messed up on your factoring

Answer 6

Got that does it some how reduce further to get x+5/x-2?

Answer 7

I wouldnt think so but I could be wrong

Answer 8

That's what I got too but then the book says the x+5/x-2 answer

Answer 9

I'm thinking the book got it wrong.

Answer 10

x^2 - 2x + 1 is a perfect square (x-1)^2 or (x -1)(x-1)

Answer 11

Think soo too cuz I know I did the process right and if you came up with the same answer then ya

Answer 12

@campbell I meant on the first denominator you messed up

Answer 13

book can be wrong again but wanna make sure.... x^2-x+11 (prime right)

Answer 14

Yes, thats prime