Question

need help fast!

Answer 1

we have k(k+1)...(k+r-1) = m * r!; m,k being positive integers.
if k doesnt divide r, then k divides m. prove it.

Answer 2

anyone ideas

Answer 3

what do mean when you put the periods?

Answer 4

k(k+1)(k+2)(k+3)(k+4)....(k+r-1) = m*r!.
k,m,r are positive integers.

Answer 5

what kind of anwser do you need?

Answer 6

a proof. see the 1st post

Answer 7

Oh. Yeah i have no clue. Sorry to waste your time :/ try looking on google? :)

Answer 8

I could be wrong in interpreting your question, but I seem to have found a counter-example.

k=21
r=3 => r! = 3!=6
so (k+r-1)=21+3-1=23

k(k+1)(k+2)=21*22*23=10626
10626 = mr! = m*3! = 6m => m= 10626/6 =1771
so
k(k+1)(k+2) = 10626=1771*3!
But 21 does not divide 1771, nor 3 so the question cannot be proved.