Question

if i could some assistance with this problem that would be great...

Answer 1

4 (l'hospitals rule)

Answer 2

thank you very much

Answer 3

you tried it and it worked out?

Answer 4

we havnt done hospitals rule yet,and i looked it yup and you take the derivative of that of both functions right?

Answer 5

yeah...take derivative of top and bottom separetly. use the same limit and evaluate. if it still tends to infinity then you can rinse repeat until it converges to a limit

Answer 6

okay im still very new to derivatives(we learned them slightly in physics) but the the derivative of the function X-1 equals 0 because the derivative of the x=1 and if i rewrite the bottom as (x-3)^-1/2 and take the take the derivative of that i get 2(x-3)^2-1 which i simplify to 2(x-3)^-1 and the i plug in my limit value which gives me 1/4^-1 or 4. is that all correct?

Answer 7

yep thats what i did

Answer 8

thank you very much

Answer 9

See if you can follow this...previous scan cut off

Answer 10

i could follow it thanks so much

Answer 11

im assuming i will start understanding them when i we start talking about them in calc because we will go in depth with them, in physics we spent one day on them

Answer 12

Yeah, usually get into limits when your learning the fundamentals of calculus. it's usually anything but exciting when your doing limits. good luck