Question

The region bounded above by the line y=6, below by the curve y=sqrt(x) and to the left by the y-axis, rotated around x=36.

Answer 1

we should get the same results if im thinking of it correctly

Answer 2

but just in case;

think of this as a solid cylinder that we are removing the under part of the sqrt(x)

Answer 3

so, cylindar itself; r=36, h=6; pi 36^2*6 is total area of this cylindar, now we gut out the area under the sqrt(x)

Answer 4

so it's like an upside down bowl

Answer 5

yes, and lets disc out the underside, i think it might integrate easier that way

Answer 6

ok after I integrated I got, 18x^2 - 2/3 * x^(3/2)