Question

Use logarithmic differentiation to find the derivative of the function: (Wolfram|Alpha didn't work)

Answer 1

what did you get after taking the natural log of both sides?

Answer 2

Thats what I'm having trouble with

Answer 3

you don't need to repost the problem I can still see it
remember all you log rules, in particular these\[\log(\frac a b)=\log a-\log b\]\[\log(x^a)=a\log x\]then you will differentiate implicitly, which will allow you to solve for y'.
why don't you try it and see how far you get?

Answer 4

rewriting this as\[y=(\frac{x^2+1}{x^2-1})^{1/6}\]should make it more clear

Answer 5

So (x^2+1)-(x^2-1) = 2?

Answer 6

not quite...\[y=(\frac{x^2+1}{x^2-1})^{1/6}\]\[\ln y=\ln(\frac{x^2+1}{x^2-1})^{1/6}=\frac1 6\ln(\frac{x^2+1}{x^2-1})=\frac1 6[\ln(x^2+1)-\ln(x^2-1)]\]now differentiate both sides implicitly.