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Find the sum of the series: the problem looks like this, a 4 over the big E looking thing (which I can't show at this time) i = -1 below, 6i - 5 right next to it.
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\[\sum_{}^{4}( 6i-5), i = \sqrt{-1}?\]
\[\sum_{i=1}^{4}\] 6i - 5
The 6i - 5 is right next to it not below it
(6*1-5) +(6*2-5) +(6*3-5) +(6*4-5) = 40
No wonder! I was looking everywhere on how to solve these type of problems. Thank you, so the answer comes out to be 40 correct?
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yup
Thanks again :D
the "big e" is called Sigma, remember sigma for SUM, have fun
Sigma, got it
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