Question

Find ( f -1 )'( a )

Answer 1

first off...by inspection \[f^{-1}(2)=0\]

Answer 2

Thats not an option

Answer 3

then use \[\left[f^{-1}\right]'(a)=\frac{1}{f'\left( f^{-1}(a) \right)}\]

Answer 4

what I pointed out was just the first step in the problem

Answer 5

Ahh, see, these are the option I am given

Answer 6

ok...use the two posts of mine above and you should get the answer.

Answer 7

So if I did this right, 4/pi?

Answer 8

no

Answer 9

only 3 options to go :)

Answer 10

lol, thats not what I'm going for

Answer 11

that won't help much come actual class time

Answer 12

\[f'(x)=2x+\sec^2(\pi x/2)\pi/2\]

\[\frac{1}{f'(f^{-1}(2))}=\frac{1}{f'(0)}=\frac{1}{\pi/2}=\frac{2}{\pi}\]

Answer 13

Oh I see, you simplified f^-1 and then you got f'

Answer 14

just combined my first two posts in this thread.

Answer 15

yeah, I'm kind of a slow/visual learner... but I'll get it

Answer 16

good

Answer 17

thanks man,

Answer 18

No problem