Mathematics
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OpenStudy (anonymous):
I NEED VECTOR HELP!!! CAN ANYONE HERE DO CAL 2 CALCULATIONS???
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OpenStudy (anonymous):
Find two unit vectors that make an angle of 60° with v = ‹6, 8›. Give your answers correct to three decimal places.
OpenStudy (anonymous):
ANYONE????
OpenStudy (anonymous):
I tried, sitting this one out. Will be watching with great interest.
OpenStudy (anonymous):
ROACHIE sorry :(
OpenStudy (anonymous):
:P
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OpenStudy (anonymous):
ill give you a medal if someone figures this out...lol
OpenStudy (anonymous):
ah!
OpenStudy (anonymous):
what is the magnitude of u?
OpenStudy (anonymous):
|v|=10
OpenStudy (anonymous):
6a + 8b = \[\left| u \right|\] (10)(1/2)
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OpenStudy (anonymous):
... u?
OpenStudy (anonymous):
by theorem 3 we need u * v = \[\left| v \right| \left| u \right|\] cos 60
OpenStudy (anonymous):
would u be 1?
OpenStudy (anonymous):
\[\sqrt{a ^{2}+b^{2}}\]
OpenStudy (anonymous):
if i knew what the magnitude of u was i could figure this problem out.
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OpenStudy (anonymous):
oh, u=<6,8>??
OpenStudy (anonymous):
right?
OpenStudy (anonymous):
u = <a,b>
OpenStudy (anonymous):
v = <6,8>
OpenStudy (dumbcow):
the magnitude of u (unit vector) is 1
i dont remember the formula for that theorem you were referring
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OpenStudy (anonymous):
yea, I dont know where u came from but yes, u being a unit vector has magnitude 1
OpenStudy (anonymous):
6a + 8b = 5 therefore b=5/8 - 3/4a
OpenStudy (anonymous):
a^2 + (5/8 -3/4a)^2 = 1
OpenStudy (anonymous):
?? any thoughts on that?
OpenStudy (dumbcow):
where does the 5 come from?
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OpenStudy (anonymous):
1/2 (10)
OpenStudy (anonymous):
u * v = |v||u| cos 60
now I see u, duh
OpenStudy (dumbcow):
why are we dividing 10 (|v|) by 2
OpenStudy (anonymous):
cos of 60 is 1/2
OpenStudy (anonymous):
someone want to factor that out for me...
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OpenStudy (anonymous):
because im sure to f THAT up.
OpenStudy (anonymous):
if we know that u is a unit vector then v * u = |v|cos 60
if you unit vector v then
v*u = cos 60
that how I think of it...
OpenStudy (anonymous):
im not following r . . . . .
OpenStudy (dumbcow):
haha...25/64 -30/32a +9/16a^2
OpenStudy (anonymous):
v-hat = v/|v|
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OpenStudy (anonymous):
then quadratic... fun fun
OpenStudy (anonymous):
|v-hat|=1
OpenStudy (anonymous):
30/32 +- \[\sqrt{30/32^{2}-4(25/64)(9/16)}/2(25/64)\]
OpenStudy (anonymous):
fml
OpenStudy (anonymous):
did you add the original a^2 to the factor? dumbcow?
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OpenStudy (dumbcow):
no i didn;t
multiply everything by 64
100a^2 -60a -39 = 0
a = -.3928, .9928
OpenStudy (anonymous):
then i need to plug those back into 5/8 -3/4a to find b right?
OpenStudy (dumbcow):
yep
OpenStudy (anonymous):
<-.3928,.9196> and <.9928, -.1196>
OpenStudy (dumbcow):
looks good
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OpenStudy (anonymous):
YES!!!!!
OpenStudy (anonymous):
thank god!