Calculate the solubility of molecules below at 25 celcius.
Oxygen in water at 3.4 atm,
given that Henry's Law constant are:
Oxygen = 1.3×10-3 molL-1atm-1
Hydrogen = 7.8×10-4 mol L-1atm-1
Nitrogen = 6.1×10-4 molL-1atm-1
Carbon monoxide = 9.5×10-4molL-1atm-1

Question

Calculate the solubility of molecules  below at 25 celcius.
Oxygen in water at 3.4 atm,
given that Henry's Law constant are:
Oxygen = 1.3×10-3 molL-1atm-1
Hydrogen = 7.8×10-4 mol L-1atm-1
Nitrogen = 6.1×10-4 molL-1atm-1
Carbon monoxide = 9.5×10-4molL-1atm-1

jfraser · Answer

Henry's Law says:$$S{_g}{_a}{_s}=k{_H}*P{_g}{_a}{_s}$$ Each molecule has its own K value, and the pressure is given (3.4atm). plug and solve.