The width of a rectangle is 7 less than twice its length. If the area of the rectangle is 113 cm^2, what is the length of the diagonal?

i did x(2x-7)=113 did the quadformula and it didnt work :\

Question

The width of a rectangle is 7 less than twice its length. If the area of the rectangle is 113 cm^2, what is the length of the diagonal?

i did x(2x-7)=113 did the quadformula and it didnt work :\

anonymous · Answer

the quad formula will give you the length of the rectangle.  from this you can get the width. Once you have the length and the width, you get the length of the diagonal by using the pythagorean theorem.

jhonyy9 · Answer

2x^2 -7x -113=0

x_1,_2=(7+/- sqrt(49+904))/4 =(7+/- sqrt953)/4 =

anonymous · Answer

Yeah I did that but you end up getting decimals and it doesnt work in the hw site for some reason.... i got 9.47 for the length and 11.94 for the width based on the equation. Idk if I did something wrong

anonymous · Answer

hmm ill check your results

jhonyy9 · Answer

so if sqrt953 =30,8 -so continue from this

anonymous · Answer

length is 9.47, width is 11.92.  Length of the diagonal is 15.2

anonymous · Answer

nope 15.2 doesnt work either :\

anonymous · Answer

hmmm

anonymous · Answer

stupid question but...it wants the length of the diagonal is cm, right?

anonymous · Answer

in*

anonymous · Answer

Yeah im assuming

anonymous · Answer

it lists _____cm though

jhonyy9 · Answer

x=37,8/4 =9,4

w=2l-7=18,8-7=11,8

diagonal d=sqrt(139.24+88,36)=sqrt227,6 =15,08

anonymous · Answer

not sure what the issue with your hw site is;  make sure you carry all your digits forward prior to rounding and other than that, your correct

anonymous · Answer

carrying all the digits worked thank you.

anonymous · Answer

ok good.. :)