Question

can someone help me with this equation: 3x^(3/2)(9 sqrt of x - 8/ sq rt of x)?

Answer 1

\[\sqrt{3}^{3}*(9*\sqrt{x}-8/\sqrt{x})\]

Answer 2

i'm sorry, i'm a little confused. is that the answer or are you asking me that's what it looks like?

Answer 3

3x^(3/2)(9 sqrt of x - 8/ sq rt of x)?
is the prob like this?
3x^(3/2) * (9 sqrt of x - 8) 3x^(3/2) * (9 sqrt of x - 8)
= -------------------------= ----------------------
( sq rt of x) x^1/2
3(9)x^(3/2) * ( x - 8)^1/2
= --------------------
x^1/2


= 27x * ( x - 8)^1/2

Answer 4

the 3x raised to the 3/2 is one part while 9 sqrt of x -(8/ sq rt of x) is all in one part.

Answer 5

I was trying to get rid of the radical beneath 8 and ended up with 8 sqrt of x all over x

Answer 6

look at my solution that 9 and 3 was multiplied and hence 9(3) (x^3/2 )(x^-1/2)=27x

Answer 7

oh! do you also multiply with the 8?

Answer 8

my solution was based on assumtion that 9 sqrt of x - 8
that you mean it is 9 (x-8)^1/2

Answer 9

no, the 8 is the numerator over the denominator sq rt of x

Answer 10

yes i know that,,, the denominator was taken care of the numerator x^3/2

Answer 11

3(9)(x^3/2 )(x^-1/2)=27x

Answer 12

that one is separate from the 9 multiplied by the sq rt of x. there are two square roots of x in this equation. one multiplied by the 9 and the one divided by the 8 which is why I assumed you multiplied the 3 with the 8 as well?

Answer 13

to get 24x right?

Answer 14

its 3(9)=27

Answer 15

kk i think i got it. sorry about the confusion. and thanks for your help.

Answer 16

3(9)x^(3/2)
------------- = 27 (x^3/2)(x^-1/2) =27x^2/2 = 27x
x^1/2

then you multipled that to sqrt(x-8)

Answer 17

kk. it just looks really confusing when first looked at. thanks

Answer 18

ok yw,,,,, good luck now...