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Last question: A rock is thrown downward from an unknown height above the ground with an initial speed of 10 m/s. It strikes the ground 3.0 s later. Determine the initial height of the rock above the ground. Question 8 options: 1) 44 m 2) 14 m 3) 74 m 4) 30 m 5) 60 m
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I only have 2 min left on the clock
I thought it would be (-10)(3.0)-1/2(9.8)(4.0) = 49
but thats not an option
\[h=v_0t+\frac1 2at^2\]because we have defined down as positive here and it was thrown down initially
a=g=9.8
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\[h=v_0t+\frac1 2gt^2=10*3+\frac1 29.8*3^2\approx?\]
74.1?
\[h=v_0t+\frac1 2gt^2=10*3+\frac1 29.8*3^2\approx74\]yep
Ah, that makes sense, Thanks man
no prob :D
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