Question

Evaluate the definite integral:

Answer 1

\[\int\limits_{4}^{7}t^3\ln(2t)dt\]

Answer 2

If I did integration by parts would the 4 and 7 be in the integral left over?

Answer 3

Wolf says 1316.95

Answer 4

Ok.... how did you get that?

Answer 5

1/16t^4(4log(2t)-1)

Answer 6

integration by parts\[u=\ln(2t)\]\[dv=t^3\]\[\int t^3\ln(2t)dt=\frac1 4t^4\ln(2t)-\frac1 4\int t^3dt=\frac1 4t^4\ln(2t)-\frac{1}{16}t^4\]\[=\frac{1}{16}t^4(4\ln(2t)-1)\]evaluate from 4 to 7
forgot parentheses earlier