A particle that moves along a straight line has velocity (see below) meters per second after t seconds. How many meters will it travel during the first t seconds?

Question

anonymous · Answer

$$v(t)=t^2e ^{-3t}$$

anonymous · Answer

integrate

anonymous · Answer

I know that, but I might need a little help on the steps.

rogue · Answer

$$Displacement = \int\limits_{0}^{t} t ^{2} e ^{-3t}dt$$

anonymous · Answer

Remember that $$v(t)=\frac{dx(t)}{dt}$$

anonymous · Answer

If you integrate like kristal said: $$x(t)=\int_0^tv(t)dt$$

rogue · Answer

$$Distance = \int\limits_{0}^{t}\left|  t ^{2} e ^{-3t} \right| dt$$

anonymous · Answer

Do you need help to solve that integral?

anonymous · Answer

I do, I know it's integration by parts. But I don't know which to make f(x) or g(x).

rogue · Answer

$$\mu = t ^{2}, d \upsilon = e ^{-3t}$$

rogue · Answer

I think, following LIPET.