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A number x is 2 more than the product of its reciprocal and its additive inverse. In what interval does the number lie?
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\[x+2=\frac{1}{x}\times (-x)\]
\[x+2=1\] \[x=-1\]
\[x=(-x)(\frac{1}{x})+2\]You have it backwards, I believe, satellite.
would the interval be \[-2<x \le0\]?
\[x=-1+2=1\]1 is two more than -1*(1/1).
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oh, if satellite had it backwards that would make sense. The interval would have to be \[0<x \le2\]
right?
The number lies in an infinite number of different intervals. \[-1290 \le x \le 2\]\[0.99999 \le x \le 4\]The question isn't specific to what interval it wants. Your answer works, though.
it's a multiple choice question so it was the only one that worked. thank you! I'm studying for the AMC 10 and it's not fun. :(
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