Question

Determine how many moles are present in 523.46g of glucse, C6H12O6

Answer 1

Same way as the last one -> C = 12g/mol, H = 1g/mol, and O = 16g/mol \[C_6H_{12}O6 = 180g/mol\]
\[523.46g * 1 mol/180g = 2.90mol\]

Answer 2

\[523.46g(glucose)*\frac{1mol(glucose)}{180.16g(glucose)}=2.9055mol(glucose)\]

Answer 3

lol to 5 sfs :p

Answer 4

Why not? :D

Answer 5

How many Sf should there be in this solution?

Answer 6

I see no reason to have less than 5. If I'm justified keeping that many sf (which you almost never are), I'm definitely going to.