Question

integrate (x+1)/(x^2+1)

Answer 1

split it up into:
\[\int\limits_{}^{}x/(x^2 +1)\]and\[\int\limits_{}^{}1/(x^2 +1)\]
the first uses substitution and the second is equal to an inverse trig function. Hope that helps

Answer 2

Break it up:
\[\int\limits\frac{x}{x^{2}+1} dx+\int\limits\frac{1}{x^{2}+1} dx\]
Then integrate it one by one

Answer 3

could you show how to integrate the second part? I'm still a little confused.

Answer 4

\[\int\limits\frac{1}{x^{2}+1} dx\]
Is an inverse trig function. When you integrate it its \[\tan ^{-1}x +C\]