Question

can anyone help me with this...
x^2/3 + 4x^1/3 + 3 = 0
How do I solve this?

Answer 1

Factorize it as : (x^(1/3)+1) (x^(1/3)+3) = 0

Answer 2

well the equation is
\[\sqrt[3]{x^2} + 4\sqrt[3]{x} + 3 = 0\]

use a substitution and let

\[u = x^ (1/3)\]

then the problem is \[u^2 + 4u + 3 = 0\]

solve for u

((u+1)(u+3)=0 u = -1,-3

then find \[x = \sqrt[3]{(-1)} \]

and
\[x = \sqrt[3]{-3}\]

are the solutions