Question

How do I solve this?
x^2/3 + 4x^1/3 + 3 = 0

Answer 1

Factorize it as : (x^(1/3)+1) (x^(1/3)+3) = 0

Answer 2

sorry, wrong didn't see the +3

Answer 3

x never equals zero though... i don't think

Answer 4

There are no solutions,I suppose

Answer 5

are you sure you wrote the problem correctly?

Answer 6

Thanks, I'm still confused...I will retype the question...

Answer 7

How do you figure that x never equals 0?

Answer 8

graphing calculator

Answer 9

@ xishem try substituting x = 0

Answer 10

Solve the equation.
x^2/3 + 4x^1/3 + 3 = 0

I think when solving for x, the equation is set equal to zero...

Answer 11

\[f(-1)=0\]

Answer 12

no, it equals 2

Answer 13

@studioso33 is it x^(2/3)

Answer 14

IT has no solutions; plot it and see

Answer 15

it has no solution as written in the real numbers, there are non-real answers however

Answer 16

\[f(-1)=x^{2/3}+4x^{1/3}+3=(-1)^{2/3}+4(-1)^{1/3}+3=1-4+3=0\]

Answer 17

SalvatoreTRM, I'm not sure? I've never typed out equations before!

Answer 18

does it look like Xishem wrote it?

Answer 19

x= -27 or -1

Answer 20

I plotted, and there are two solutions.

Answer 21

Sorry, I'm new here...you guys are far more advanced at math than I! Yes, looks like Xishem wrote it...

Answer 22

ok then yes, Ireneoseaspe is right and Xishem as well. x=-27 and -1

Answer 23

Xishem, how to I plot and find solutions myself? Are you all using graphing calculators?

Answer 24

Why is Wolfram plotting it like this?

http://www.wolframalpha.com/input/?i=x%5E%282%2F3%29%2B4x%5E%281%2F3%29%2B3

Answer 25

@studio: I didn't find the original solutions graphically, but rather by factoring and setting each of the factors equal to zero separately.

Answer 26

Ok, i take it back, no solutions. Viva wolfram

Answer 27

Thank you all...it will take time for me to get used to this online tutoring...I will be in here ALOT!

Answer 28

Wolfram is wrong. Take a look at THIS plot, which is just a factorization of the original.

http://www.wolframalpha.com/input/?i=%281%2Bx%5E%281%2F3%29%29+%283%2Bx%5E%281%2F3%29%29&lk=1&a=ClashPrefs_*Math-

Both the math and my graphing calculator tell me that there are two solutions.

Answer 29

http://www.wolframalpha.com/input/?i=cos%5E-1++%28-1%29

Answer 30

who is wolfram?

Answer 31

\[(x^{1/3}+1) (x^{1/3}+3) = 0\]\[x^{1/3}+1=0 \rightarrow x^{1/3}=-1 \rightarrow x=(-1)^3 \rightarrow x=-1\]You can't deny that there are solutions.

Answer 32

@studio
website

Answer 33

If you put x = -1 you get 3 not 0

Answer 34

x^2/3 + 4x^1/3 + 3 = 0
u=x^1/3
u^2 + 4u + 3 = 0
(u + 3)(u + 1) = 0
u= -3,u= - 1

u=x^1/3
-3 = x^1/3
(-3)^3 = (x^1/3)^3
-27 = x

u=x^1/3
-1 = x^1/3
(-1)^3 = (x^1/3)^3
-1 = x

Answer 35

Aron: Show your work. I get 0 every time.

Answer 36

@Irene if you substitute the values you wont get 0.

Answer 37

Xishem, do you know robby mayasich?

Answer 38

nvm, your profile pic reminded me of someone

Answer 39

http://www.wolframalpha.com/input/?i=%28-1%29%5E%281%2F3%29

Wolfram also thinks that is true. Weird.

Answer 40

And that error would explain why WolframAlpha doesn't give the correct answers.

Answer 41

(x^(1/3)+1) (x^(1/3)+3) = 0

Answer 42

x^2/3 + 4x^1/3 + 3 = 0
(-27)^2/3 + 4(-27)^1/3 + 3 = 0
\[\sqrt[3]{-27^{2}} + 4\sqrt[3]{-27} + 3 = 0\]
\[\sqrt[3]{729} + 4(-3) + 3 = 0\]
\[9 -12 + 3 = 0\]
\[-3 + 3 =0\]
0=0