Find the shortest distance from the line 2x+6y=3 and passing through the point (9,-7)

Question

mertsj · Answer

That would be the perpendicular distance so you must first find the equation of the perpendicular through( 9,-7) that has slope 3.

mertsj · Answer

Do that and we'll go from there.

anonymous · Answer

can yu show me how to do it?

anonymous · Answer

If memory serves, $\huge \frac{ 2(9)+6(-7)-3 } { \pm \sqrt{2^2+6^2 } }$

mertsj · Answer

Can you find the equation of a line whose slope is 3 and contains the point (9,-7)?

mertsj · Answer

Oh.  I see that Fool wants to help you now so I'll turn you over to him.

anonymous · Answer

lol yu can still help me

anonymous · Answer

im not sure if yur suppose to use the quadratic formula for this

mimi_x3 · Answer

THe formula for this, i think:
$$\large \frac{ax_{1}+by_{1}+c}{\sqrt{a^{2}+b^{2}}}  $$

anonymous · Answer

there is a formula for it

anonymous · Answer

The proof  requires representing the lines in normal form and then finding the perpendicular distances.

anonymous · Answer

Mimi, your formula is close but not apt, it should be Either,  $$ \large \pm\frac{ax_{1}+by_{1}+c}{\sqrt{a^{2}+b^{2}}} $$ or $$ \large \frac{|ax_{1}+by_{1}+c|}{\sqrt{a^{2}+b^{2}}} $$


Recall, Euclidean distance cannot be negative :)

mimi_x3 · Answer

lol, yeah i forgot my bad.

anonymous · Answer

no worries, as long as you give me medal :P

mimi_x3 · Answer

obssessed of medals huh :P

anonymous · Answer

whats the point of medals?
do yu get nythin

anonymous · Answer

hehe, not really it's fun though.

mimi_x3 · Answer

You get nothing, just a level, it just a waste of time anyway :P

anonymous · Answer

Why should I answer you? Will I get anything? 

What is the purpose of anything in life? Life is as meaningless itself as this discussion :P

anonymous · Answer

LMAO ^

mimi_x3 · Answer

Lol, life is cruel.

anonymous · Answer

;)