Question

An elevator starts from rest with a constant
upward acceleration and moves 1 m in the first
1.8 s. A passenger in the elevator is holding a
8.7 kg bundle at the end of a vertical cord.
What is the tension in the cord as the elevator accelerates? The acceleration of gravity
is 9.8 m/s^2
Answer in units of N

Answer 1

Over the first meter we can find the acceleration of the elevator\[x=\frac1 2at^2\]Where x and t are given in the problem.
The tension force on the string will be equal to the force of gravity, plus the force due to the acceleration of the elevator.\[ T=F_g+F_E=mg+ma\]