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Mathematics 14 Online
OpenStudy (anonymous):

What is my inner-function g if I integrate x/(2-x)^3 with the method of substitution?

OpenStudy (escherichiarinku):

If you think of powers as a function, then you will easily see that (2-x) is a function inside the power function. So, your g is g(x) = 2-x.

OpenStudy (anonymous):

that was simpler than it looked :S

OpenStudy (anonymous):

Escher, if you actually did that by integration, what would it look like?

OpenStudy (anonymous):

then of course you have to write \[u=2-x, du = -dx\] \[x=2-u\] and integrate \[-\int \frac{2-u}{u^3}du\]

OpenStudy (anonymous):

or if you prefer \[\int \frac{u-2}{u^3}du\]

OpenStudy (escherichiarinku):

And then substitute (2-x) back to get a result with the original terms :)

OpenStudy (escherichiarinku):

^I mean, substitute (2-x) back after integration :D

OpenStudy (anonymous):

Oh, I did not know that I´m also able to replace the x upstairs (which annoyed) with 2-u. Thank you very much.

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