Question

Factor:

Answer 1

im waiting :P

Answer 2

\[5yz ^{2}-35yz+10y ^{2}z\]

Answer 3

5 yz ( 5z - 7 + 2y)

Answer 4

WOoOOOooooOooooOooooo :P

Answer 5

5yz(z - 7 + 2y)

Answer 6

wait...-.- its z not 5z inside the bracket

Answer 7

5 yz ( z - 7 + 2y) soorry

Answer 8

x(y-3) -4(y-3)

Answer 9

you want us to factor that?

Answer 10

do yu simplify it first

Answer 11

and ya factor it

Answer 12

its already factored tho: i guess you can use distributive property and then factor it as a whole

Answer 13

(y-3) (x-4)?

Answer 14

is tht the ans

Answer 15

my bad :P
yes it is

Answer 16

Go Charmi :D

Answer 17

^__^

Answer 18

lol any other ones :P

Answer 19

2mn+3mp-4n-6p

Answer 20

2n(m-2) + 3p (m-2)

Answer 21

well for this one you have to find a variable thats common to all the coefficients
but i dont think its possible to factor this

Answer 22

(m-2) (2n+3p)

Answer 23

wait

Answer 24

yeah use grouping :O

Answer 25

im losing myself

Answer 26

so is it right?

Answer 27

aha

Answer 28

\[x^{2}-12x+20\]

Answer 29

= 2mn+3mp-4n-6p
= (2mn - 4n) + ( 3mp - 6p)
= 2n( m - 2) + 3p (m - 2)
= (2n + 3p) (m-2)

Answer 30

\[x ^{2} - 12x + 20 \]

Answer 31

yup

Answer 32

\[x ^{2} - 10x - 2x + 20 \]\[(x ^{2} - 2x) + (-10x +20)\] \[x(x-2) -10 (x - 2)\] \[(x - 10) (x - 2)\]

Answer 33

i didnt lose myself :P

Answer 34

yu need 2 numbers tht multiply to 20 and add to 6 right

Answer 35

two numbers that add to 12 and multiply to 20 *

Answer 36

not 6

Answer 37

oh my bad :P

Answer 38

lol dw we all make mistakes P:

Answer 39

im lost :/

Answer 40

on what yu did

Answer 41

umm so basically what i did is that i found that -2 x -10 is equal to positive 20 and add to -12

(negative)x(negative) = positive

Answer 42

oh ok :P

Answer 43

thanks :D

Answer 44

and r yu sure its not (x-2) (x-10)

Answer 45

or it doesnt matter wht way yu put it as

Answer 46

it doesnt really matter as long as you can get the equation you started with
i believe it looks better for communication the way you put it

Answer 47

\[y^{2}+3y-18\]

Answer 48

ok for this one you want a number that adds up to 3 and multiplies to get -18
so you're gonna need a negative and a positive number

Answer 49

any ideas of multiples

Answer 50

i was stuck
here:

y(y+6) -3 (y+6)

Answer 51

wud it be

(y+6) (y-3)

Answer 52

someone cheer for her
that's right
you had the answer the whole time <3

Answer 53

WOOOOO:P

Answer 54

buhh cant yu still divide it
cause theres a 3 and a 6?

Answer 55

or jus leave it like tht :P

Answer 56

lol i believe you can leave it like that :D

Answer 57

aha ok :P

Answer 58

\[x^{2}-18\]

Answer 59

shud i leave the middle number as 0

Answer 60

what do you think this one is

Answer 61

how wud yu do this
i forgot :$

Answer 62

(a - b) (a+ b)
the middle number is eliminated :)

Answer 63

(x-6) (x+6)?

Answer 64

no wait (x-6) (x+3)

Answer 65

i believe the middle number is missing
cuz you cant factor that

Answer 66

yu cant?

Answer 67

so yu dun do nytiin to it?

Answer 68

well no matter how much we factor it
it wont match the question after factoring

Answer 69

good job dada