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Mathematics 17 Online
OpenStudy (anonymous):

Is this a contradiction? On this problem they ask: Use the definitions of the hyperbolic functions to find the following limit: lim x->infinity sinhx However the answer is either: lim x->0^- coth(x) = -infinity or lim x->0^+ coth(x) = infinity Anyone see what I'm doing wrong? I'm attaching the original problem

OpenStudy (anonymous):

OpenStudy (anonymous):

Any ideas?

OpenStudy (anonymous):

i'm not sure what you're asking...

OpenStudy (anonymous):

are you sure the put the right attachment

OpenStudy (anonymous):

I'm sorry, my bad, mistyped the uploaded file

OpenStudy (anonymous):

I'll take that as no one is sure what to do...

OpenStudy (anonymous):

do you know the standard algebraic expressions for the hyperbolic functions?

OpenStudy (anonymous):

x = sinh x = (e^x - e^-x)/2

OpenStudy (anonymous):

* sinhx = sinh x = (e^x - e^-x)/2

OpenStudy (campbell_st):

well use the definition \[\sinh (x) = (e^x - e^(-x))/2\] so its the \[\lim_{x \rightarrow \infty} (e^x - e^(-x))/2\] rewriting \[\lim_{x \rightarrow \infty} e^x/2 - \lim_{x \rightarrow \infty} 1/(2e^x)\] 2nd part approaches 0 as x approaches infinity 1st part has approaches infinity

OpenStudy (anonymous):

Ah, I see, thats kind of a strange problem

OpenStudy (anonymous):

thanks!

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