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OpenStudy (anonymous):
How do I simplify this expression: √3 / √3 + √2? The answer is 3 - √6... how?
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OpenStudy (anonymous):
is sqrt(2) in the denominator?
OpenStudy (anonymous):
no, there's no root 2 in the denominator
OpenStudy (ash2326):
\(\sqrt 3/( \sqrt 3+ \sqrt 2)\)
now multiply numerator and denominator by \(\sqrt 3- \sqrt 2\)
we have
\( \sqrt 3/( \sqrt 3 + \sqrt 2) *( \sqrt 3 - \sqrt 2)/( \sqrt 3 - \sqrt 2)\)
we get \[ (3-2 \sqrt 6)/( 3-2)\]
or
\[3-2\sqrt 6\]
OpenStudy (ash2326):
sorry it'd be \[3-\sqrt 6\]
OpenStudy (anonymous):
why is it 3 - 2√6?
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OpenStudy (ash2326):
ignore the 2 int the last two steps
OpenStudy (ash2326):
did you get??
OpenStudy (anonymous):
but why is it 3 - √6? Did you cancel something?
OpenStudy (ash2326):
when we multiplied \(\sqrt 3 -\sqrt 2\) in the numerator and denominator , denominator became 1 . and numerator became
\[3-\sqrt 6\]
OpenStudy (anonymous):
can you please show me? I'm still confused about what you just said.. so sorry D:
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OpenStudy (ash2326):
|dw:1327812623013:dw|
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