How do I simplify this expression: √3 / √3 + √2? The answer is 3 - √6... how?

Question

anonymous · Answer

is sqrt(2) in the denominator?

anonymous · Answer

no, there's no root 2 in the denominator

ash2326 · Answer

$\sqrt 3/( \sqrt 3+ \sqrt 2)$
now multiply numerator and denominator by $\sqrt 3- \sqrt 2$
we have 
$ \sqrt 3/( \sqrt 3 + \sqrt 2) *( \sqrt 3 - \sqrt 2)/( \sqrt 3 - \sqrt 2)$
we get $$ (3-2 \sqrt 6)/( 3-2)$$
or 
$$3-2\sqrt 6$$

ash2326 · Answer

sorry it'd be $$3-\sqrt 6$$

anonymous · Answer

why is it 3 - 2√6?

ash2326 · Answer

ignore the 2 int the last two steps

ash2326 · Answer

did you get??

anonymous · Answer

but why is it 3 - √6? Did you cancel something?

ash2326 · Answer

when we multiplied $\sqrt 3 -\sqrt 2$ in the numerator and denominator , denominator became 1 . and numerator became
$$3-\sqrt 6$$

anonymous · Answer

can you please show me? I'm still confused about what you just said.. so sorry D:

ash2326 · Answer

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