Question

The angle of minimum deviation for a prism of refractive index 3/2 is equal to angle of prism. What is the angle of the prism? ( cos 41 = 0.75)
a) 31 degrees
b) 41 degrees
c) 62 degrees
d) 82 degrees

Answer 1

\[\mu=\sin ((A+\delta)/2)/\sin(A/2)\] here delta = A
The RHS becomes sin(A)/sin(A/2)=2cos(A/2)=3/2
cos(A/2)=0.75
A/2=41
A=82.