Question

Why ln(i)=(1/2)*pi*i?

Answer 1

The situation actually was \[i^i=e^{i*lni}=e^{i(1/2)\pi*i}=e^{-(1/2)\pi}\]

Answer 2

yh, use Euler's formula

Answer 3

\[e ^{i}e ^{lni}\]

Answer 4

How does \[e^{i \pi}=-1\] help here, or is there another part of the formula that I;m missing?

Answer 5

\[lni=i \pi/2\]

Answer 6

OK, Thanks. Could you point me to an article with the proof?

Answer 7

http://www.wolframalpha.com/input/?i=lni