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Physics 16 Online
OpenStudy (anonymous):

an object is 375mm in front of a concave mirror that is the focus of 250mm. if the object is moved 25mm approached the mirror, the image will be shifted as far

OpenStudy (anonymous):

Use the mirror formula and finid the solution.

OpenStudy (anonymous):

how to solve that?

OpenStudy (anonymous):

For concave mirror, foacl length is negative. Object distance always negative. The mirror formula is: (1/u) + (1/v) = (1/f) where, u = object distance, v = image distance, and f = focal length Better to convert all units in terms of "metres".

OpenStudy (anonymous):

(1/s)+(1/s') = (1/f) (1/s') = (1/f)-(1/s) (1/s') = (1/-250)-(1/375) (1/s') = -(1/150) or - 0.00667 mm when the object moved 25 mm object -> 375 mm - 25 mm = 350 mm (1/s)+(1/s') = (1/f) (1/s') = (1/f)-(1/s) (1/s') = (1/-250)-(1/350) (1/s') = - 0.00686 mm \[\Delta s' = -0.00667 mm - (-0.00686 mm) \]So the image object moved -> 0.00019 mm

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