an object is 375mm in front of a concave mirror that is the focus of 250mm. if the object is moved 25mm approached the mirror, the image will be shifted as far
Use the mirror formula and finid the solution.
how to solve that?
For concave mirror, foacl length is negative. Object distance always negative. The mirror formula is: (1/u) + (1/v) = (1/f) where, u = object distance, v = image distance, and f = focal length Better to convert all units in terms of "metres".
(1/s)+(1/s') = (1/f) (1/s') = (1/f)-(1/s) (1/s') = (1/-250)-(1/375) (1/s') = -(1/150) or - 0.00667 mm when the object moved 25 mm object -> 375 mm - 25 mm = 350 mm (1/s)+(1/s') = (1/f) (1/s') = (1/f)-(1/s) (1/s') = (1/-250)-(1/350) (1/s') = - 0.00686 mm \[\Delta s' = -0.00667 mm - (-0.00686 mm) \]So the image object moved -> 0.00019 mm
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