Question

19. Balance the following redox reaction using the half-reaction method under acidic conditions. Identify the oxidizing agent and reducing agent.
Cr2O72- + I- -----> Cr3+ + I2

Answer 1

6e + 14H+ + Cr2O7 2- - > 2 Cr3+ + 7H2 O [reduction] so means Cr2O7 2- is oxidizing agent

2I- -> I2 + 2e )x3 [oxidation] so means I- is reducing agent

and then u juz need to balance it out :) I did it quite fast..so hope there is no mistake