19. Balance the following redox reaction using the half-reaction method under acidic conditions. Identify the oxidizing agent and reducing agent.
Cr2O72- + I- ----- Cr3+ + I2

Question

19.	Balance the following redox reaction using the half-reaction method under acidic conditions.  Identify the oxidizing agent and reducing agent.
Cr2O72- + I-   -----> Cr3+ + I2

anonymous · Answer

6e + 14H+  + Cr2O7 2- - > 2 Cr3+ + 7H2 O  [reduction] so means Cr2O7 2- is oxidizing  agent

2I- -> I2 + 2e  )x3  [oxidation] so means I- is reducing agent 

and then u juz need to balance it out :) I did it quite fast..so hope there is no mistake