a jazz concert brought in $135,000 on the sale of 8600 tickets. if the tickets were sold for $10 and $20 each, how many of each type of ticket were sold?

Question

anonymous · Answer

simultaneous equations

1) $$x + y = 8600$$

2) 10x + 20y = 135000

solve for either x or y and substitute into other equation

anonymous · Answer

10x + 20y = 135,000
x+y=8600

y= 8600 - x

10x + 20 (8600 - x)= 135, 000
10x +172,000 - 20x = 135,000
-10x + 172,000= 135,000
-10x = -37000
x= 3700 ($10 tickets)

3700 + y = 86000
y= 82,300 (20 tickets)

anonymous · Answer

let's see x = 8600 - y
so 10(8600-y) + 20y = 135000
86000 -10y +20y = 135000
10y = 49000
y = 4900
x = 8600 - 4900 = 3700

anonymous · Answer

@ nicole you got one to many zeros in your last equation