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Mathematics 10 Online
OpenStudy (anonymous):

can someone check my answer: |2x+5|-1<6 add -1 |2x+5|<7 2x+5>-7 subtract 5 2x>-12

OpenStudy (precal):

when you drop the asolute value it should be \[-7<2x+5<7\]

OpenStudy (anonymous):

does that mean my answer is wrong?

OpenStudy (precal):

yes because you never switch the inequality from less than to greater than unless you multiply by a negative number or if you divide by a negative number. subtract 5 to all sides and then divide by 2

OpenStudy (precal):

\[-12<2x<2\] \[-6<x<1\] Your solution is from -6 to 1 but not including -6 or 1 just the numbers in between

OpenStudy (anonymous):

why do i subract 5?

OpenStudy (precal):

or add -5 same thing and it is because you want to move it to the other side

OpenStudy (anonymous):

do i subtract if from the -1 or the 6?

OpenStudy (precal):

\[\left| 2x+5 \right|-1<6\] add 1 to both sides \[\left| 2x+5 \right|<7\] drop absolute value \[-7<2x+5<7\] subtract 5 to all 3 sides \[-12<2x<2\] divide by 2 to all 3 sides \[-6<x<1\]

OpenStudy (precal):

hope that helps

OpenStudy (anonymous):

if i were to graph it on a number line what would it look like? as in wouldi t point to the left?

OpenStudy (precal):

put hollow circles on -6 and 1 that shows that they are not included and shade in between those two numbers. -5, -4, -3, -2, -1, 0 are solutions but so are -5.999 to .99999

OpenStudy (anonymous):

|dw:1327885941882:dw|ok so i put the circles on -6 then shade to the right and i put circles on 1 and shade to the left?

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