can someone check my answer: |2x+5|-1<6 add -1 |2x+5|<7 2x+5>-7 subtract 5 2x>-12
when you drop the asolute value it should be \[-7<2x+5<7\]
does that mean my answer is wrong?
yes because you never switch the inequality from less than to greater than unless you multiply by a negative number or if you divide by a negative number. subtract 5 to all sides and then divide by 2
\[-12<2x<2\] \[-6<x<1\] Your solution is from -6 to 1 but not including -6 or 1 just the numbers in between
why do i subract 5?
or add -5 same thing and it is because you want to move it to the other side
do i subtract if from the -1 or the 6?
\[\left| 2x+5 \right|-1<6\] add 1 to both sides \[\left| 2x+5 \right|<7\] drop absolute value \[-7<2x+5<7\] subtract 5 to all 3 sides \[-12<2x<2\] divide by 2 to all 3 sides \[-6<x<1\]
hope that helps
if i were to graph it on a number line what would it look like? as in wouldi t point to the left?
put hollow circles on -6 and 1 that shows that they are not included and shade in between those two numbers. -5, -4, -3, -2, -1, 0 are solutions but so are -5.999 to .99999
|dw:1327885941882:dw|ok so i put the circles on -6 then shade to the right and i put circles on 1 and shade to the left?
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