Question

solve the differential equation y''+y'-3y=0.

Answer 1

\[r^2+r-3=0 => r=\frac{-1 \pm \sqrt{1 - 4(-3)}}{2}=\frac{-1 \pm \sqrt{13}}{2}\]
this implies
\[y=c_1 e^{\frac{-1+ \sqrt{13}}{2}}+c_2e^\frac{-1 - \sqrt{13}}{2}\]

Answer 2

oops missing something

Answer 3

yeah, its sqrty

Answer 4

\[y=c_1 e^{\frac{-1+ \sqrt{13}}{2}x}+c_2e^{\frac{-1 - \sqrt{13}}{2}x}\]

Answer 5

i was missing the little x

Answer 6

I know I can count on someone here Thank you all.

Answer 7

:)