Question

The line containing the longer diagonal of a quadrilateral whose vertices are A (2, 2), B(-2, -2), C(1, -1), and D(6, 4).

Answer 1

calculate AC and BD using distance formula and the longer one will be the line containing the longer diagonal of the quadrilateral

Answer 2

so x-y=9?

Answer 3

or 2x+1y=9

Answer 4

AC = sqrt[(x2 - x1)^2 + (y2 - y1)^2]

Answer 5

AC = sq.rt[(1 - 2)^2 + (-1 -2)^2]
ac = sqrt[(-1)^2 + (-3)^2]
AC = sqrt[1 + 9]
ac = sqrt(10)

Answer 6

similarly calculate BD

Answer 7

B(-2, -2), D(6, 4).
BD = sq.rt{[6 - (-2)]^2 + [4 -(-2)]^2}
BD = sqrt[(6 + 2)^2 + (4 + 2)^2]
BD = sqrt[(8)^2 + (6)^2]
BD = sqrt(64 + 36)
BD = sqrt(100)
BD = 10

so BD is the longer one

Answer 8

can you help me with another equation

Answer 9

sure, go ahead..

Answer 10

Indicate the equation of the given line in standard form.
The line containing the median of the trapezoid whose vertices are R(-1, 5) , S(l, 8), T(7, -2), and U(2, 0).

This is the question... and for the answer i got was:
13+x-y=48? can you tell me where i went wrong

Answer 11

We can first find the midpoints of the legs RU and ST using the Midpoint formula of a line segment.
Then we find the distance between them by using the formula for Distance between Two Points.