Can someone explain how we use an integral to find the area?
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This is a circle or a sphere?
Hey ishaan
It is a circle
I knwo the steps but I dont get what i am doing
Where is the trouble? ..also is any information given regarding this chord? .. what angle it suspends .. and is the width of the chord comparable to the radius?
nooo just show some arrows and a h
Have you discussed polar integration yet? I doubt it, but just to be sure.... -.-
no
like the book used pythagorean theroem in the begginning. in order to get the equation of the integral
I guess everybody fell asleep at the comp like me -_-
No, but it seems rivermaker is typing a very length reply, so I was waiting to see ;)
lengthy*
hehe I was just teasing :D
river are you still going, or is it saying you're typing by mistake?? haha
|dw:1327897236799:dw| Let us take any function y = f(x) THe area under the curve y = f(x) is the sum of rectangular strips (like one shown near rhe middle of the picture) if you assume the co-ordinates of the strip as \[(x_{0}, 0), (x_{0}, y_{0}), (x_{1}, y_{1}), (x_{1},0) \] then the area of the strip is approximated by \[y_{0} \times (x_{1} - x_{0}) \] So the area under the curve is the sum of such strips \[\sum_{x=a}^{x=b}f(x) \Delta x, \] where \[\Delta x \] is the width of the strip at \[x\] Going to the limit as \[\Delta x \rightarrow 0, \] we get the area as \[\int\limits_{a}^{b} f(x) dx\]
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