Question

what is the integral of 0 to pi of cos(x+pi)dx

Answer 1

is equal to\[-\int\limits_{0}^{\pi}\cos x dx\]

Answer 2

0

Answer 3

\[\int_{0}^{\pi} cos (x+\pi) dx\]
integration of cos x= sin x
so
we get
\[sin(x+\pi)\]
\[sin(2\pi)-sin(\pi)\]
so
\[0-0\]
0