Use the quadratic formula to solve x2 + 5x = –2

Question

hero · Answer

rewrite it as 

x^2 +5x + 2 = 0

hero · Answer

a = 1
b = 5
c = 2

Plug that into the formula and solve

hero · Answer

By the way, the formula is

$$x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

anonymous · Answer

$$x^2 + 5x = -2 $$ should be rearranged such the Right Hand Side (RHS) is 0. You can do that by adding 2 to both sides of the equation.

anonymous · Answer

That would make it $$x^2 + 5x + 2 = 0$$

the quadratic formular is $$(-b \pm \sqrt{b^2 - 4ac})/2a$$

a is the coeffecient of x^2 so a = 1
b is the coeffecient of x so b = 5
c is the constant term so c = 2

anonymous · Answer

So my answer would be -5sqrt17/2?

anonymous · Answer

$$-5\pm \sqrt{17}$$

anonymous · Answer

Where would the 2 go?

anonymous · Answer

You mean the 2 that was on the RHS ?
It would come over to the LHS and become the constant term

anonymous · Answer

Oh sorry. My mistake. I see what you mean

$$(-5\pm \sqrt{17})/2$$

anonymous · Answer

I hope I got it right this time :)

anonymous · Answer

Okay thank you so much :)