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Chemistry 9 Online
OpenStudy (anonymous):

how many moles are in 120 g N2?

OpenStudy (xishem):

\[120g(N_2)*\frac{1mol(N_2)}{28.01g(N_2)}=4.28mol(N_2)\]

OpenStudy (preetha):

Very nicely done Xishem. We need you to come here more often to help in Chem.

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