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OpenStudy (anonymous):
how many moles are in 120 g N2?
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OpenStudy (xishem):
\[120g(N_2)*\frac{1mol(N_2)}{28.01g(N_2)}=4.28mol(N_2)\]
OpenStudy (preetha):
Very nicely done Xishem. We need you to come here more often to help in Chem.
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