Question

Suppose f(x)=A+x for x < 2 and f(x) =5 + x^2 for x greater/equal to 2. Find a value of A such that the function f(x) is continuous at the point x=2.

A=

Answer 1

pizza: its the same prob i posted earlier

Answer 2

f(x) =5 + x^2
f(2)=9

so 9=A+2
A=7

Answer 3

\[x \rightarrow -2, x \rightarrow 2\] must give the same value of f

Answer 4

so u have what pizza did above ^

Answer 5

basically f(2)=lim x->(2+) f(2)=lim x->(2-) f(2)

Answer 6

btw it is a typo i meant\[x \rightarrow 2 ^-\] not\[x \rightarrow-2\] :P

Answer 7

ok i think i got it lol