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if du/dx=2x+6 what does du equal? this is using substitution for solving an indefinite integral.
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i guess \[du=(2x+6)dx\] what is the actual problem?
du = (2x + 6)dx You can now integrate both sides to solve for u
\[u = x^2 + 6x + C\]
\[\int\limits_{?}^{?} x+3/(x^2+6x)^2 dx\]
oh ok \[u=x^2+6x\] \[du= (2x+6)dx\] \[\frac{1}{2}du=(x+3)dx\] and then you get \[\frac{1}{2}\int \frac{1}{u}du\]
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a set up for a u - sub. then anti derivative is \[\frac{1}{2}\ln(u)\] , replace u by \[x^2+6x\] and you are done
omg thank you sooooo much!!!
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