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Which of the following compounds contains a greater percentage of water by mass, SnCl2 . 2H2O or NaC2H3O2 . 3H20?
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Compound 1:\[1mol(SnCl_2)*\frac{189.62g(SnCl_2)}{1mol(SnCl_2)}=189.62g(SnCl_2)\]\[2mol(H_2O)*\frac{18.02g(H_2O)}{1mol(H_2O)}=36.04g(H_2O)\]\[Percent(H_2O)_{mass}=\frac{mass(H_2O)}{mass(SnCl_2·2H_2O)}\]\[Percent(H_2O)_{mass}=\frac{36.04g}{189.62g+36.04g}=0.1597=15.97percent\] Now for compound two, you would go through a similar process. Go ahead and try to do it for compound and see if you can come up with an answer.
By the way, for the second compound you should get... \[0.3972=39.72percent\]Therefore, the second compound contains a greater percentage of water by mass.
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