Which of the following compounds contains a greater percentage of water by mass, SnCl2 . 2H2O or NaC2H3O2 . 3H20?

Question

xishem · Answer

Compound 1:$$1mol(SnCl_2)*\frac{189.62g(SnCl_2)}{1mol(SnCl_2)}=189.62g(SnCl_2)$$$$2mol(H_2O)*\frac{18.02g(H_2O)}{1mol(H_2O)}=36.04g(H_2O)$$$$Percent(H_2O)_{mass}=\frac{mass(H_2O)}{mass(SnCl_2·2H_2O)}$$$$Percent(H_2O)_{mass}=\frac{36.04g}{189.62g+36.04g}=0.1597=15.97percent$$
Now for compound two, you would go through a similar process.

Go ahead and try to do it for compound and see if you can come up with an answer.

xishem · Answer

By the way, for the second compound you should get...
$$0.3972=39.72percent$$Therefore, the second compound contains a greater percentage of water by mass.