Question

can anyone help me figure out a new equation for an ellipse whose length and width are doubled and the original equation is x^2/50+y^2/20=1

Answer 1

Find out a & b. Multiply them with 2. & put'em in the general equation of the ellipse. :)

Answer 2

KDroid is correct, but I'll give you a bit more:

You want to take the square root of the numbers in the denominator of the 'x' and 'y' slots to get 'a' and 'b' (so 50 and 20 respectively; square root to get a=7.07 and b =4.46). That will give you the points on the x-axis and y-axis of which your ellipse crosses.

Double this number and re-square it to get it back in the form you started in.

So, \[\sqrt{50} = 7.07\]
\[7.0*2 = 14.1421\]
\[14.1421^{2} = 200\]
200 is the new value under your 'x'.

Do the same for the 'y' and you should get 80.