please help! What is the slope of a line that passes through the point (-2, 3) and is parallel to a line that passes through (3, 7) and (-2, -8)?
=-8-7/-2-3 =-15/-3 =5
\[{ (-8-7) \over (-2-3) }= 5\] This will be slope of the every parallel line, that is parallel to this line.
the equation of the line form is: y-3=5(x+2) y-3=5x+10 5x-y+13=0
I like you name haha_proof :D
thanks..im not really good in math as you think..
Thanks for all of your help :) and thank you :D
Glad to help :)
can you please help with one more im doing this exam and im so lost on these type of problems and i have to get a good grade.?
you're welcome ...its our pleasure to solve math problems,hehe
What is the slope of the line passing through the point (3, -4) and perpendicular to the line y = 3x + 5? Write your answer as a fraction.
what you are going to do is that familiarize the different form of the line equation.
y=3x+5 is in the form of slope intercept form where y=mx +b. so the slope is m=3. to get perpendicular slope of the given line you need to get the multiplicative inverse that will result to -1 so the slope is m=-1/3
Thank you for all of your help :) im still a little confused but ill try my next problem on own!
*my own
ok,just remember that parallel lines do have the same slope and perpendicular lines get -1 if slopes are to be multiplied.
ok thanks again!
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