You have a committee of 13 members, made up of 8 men and 3 women. In how many ways can 3 tasks be assigned so that both men and women are given assignments?

Question

You have a committee of 13 members, made up of 8 men and 3 women.  In how many ways can 3 tasks be assigned so that both men and women are given assignments?

anonymous · Answer

The number of ways in which 3 tasks can be distributed such that only men or only women get the job is.
Only men 8C3
Only women : 3C3=1
Total ways: 13C3
Hence the answer would be 13C3-1-8C3

anonymous · Answer

ill work it out

anonymous · Answer

that wasnt right

anonymous · Answer

Hmm okay maybe it was wrong i am not sure....

anonymous · Answer

would it be a permutation

anonymous · Answer

No i think it'll be a combination only.

anonymous · Answer

One task is given to one person only right?

anonymous · Answer

it just says how many ways can the 3 tasks be assigned so that both women and men are given assignments

dumbcow · Answer

is that a typo?
shouldn't it be 8 men and 5 women

anonymous · Answer

total 13 members and 3 total tasks

anonymous · Answer

Is 220 the answer?

anonymous · Answer

no

dumbcow · Answer

shankvee had the right idea :)
but your numbers don't add up ....8+3 = 11 not 13

anonymous · Answer

leave u cant read 8+5

dumbcow · Answer

??
13C3 - 8C3 - 5C3 = 286 - 56 - 10 = 220

anonymous · Answer

sorry thought you were messing with me i am so sorry
but 220 is not right

dumbcow · Answer

maybe it is permutations then....
13P3 - 8P3 - 5P3 =  1320

anonymous · Answer

you are a genius

anonymous · Answer

It was permutations

anonymous · Answer

I am so sorry for my comment earlier I had some punk on here earlier and thought you were messing with me

anonymous · Answer

I am very very sorry

dumbcow · Answer

no prob, just noticed a typo in your question post

anonymous · Answer

I am so sorry

anonymous · Answer

I have tried the problem 40 times

dumbcow · Answer

do you know the formulas for combinations and permutations?

most calculators will do them for you as well

anonymous · Answer

somewhat...i find them confusing and hard to remember
also my finite course does not allow calculators during exams so i am trying to do them manually because all of our test questions come from these particular set of problems

anonymous · Answer

I have a few more permuations and maybe a combo i am going to post that are two part questions....3-5 of these have stumped me, most i can work through

directrix · Answer

Should this 13 be 11? Or, are the other two committee members neither female nor male? Just wondering.

13 members, made up of 8 men and 3 women. 8+3 =11. I don't think this is a permutation problem. I could be wrong but what about the 13 committee - those two extra members?