How many kilograms are in 4 moles of Na2CO3?
Whats the molar mass of that? I don't have a periodic table so I keep asking
Molar mass of Na2CO3 is 105.9886 g/mol
\[4 mole Na_2CO_3(\frac{105.99 g Na_2CO_3}{1 mole Na_2CO_3})(\frac{1 kg}{1000 g })=.424 kg Na_2CO_3\]
Is the equation loading or does it look all crazy for you?
Looks fine:)
ok cool
let me first tell u how to calculate molar mass ok? u need to find of Na2CO3 so add the molar masses of the elements together multiplying them with their respective subscripts so here it goes like this Na= 23 C=12 O=16 so Na2CO3=2(23)+12+3(16)=46+12+48=96
\[46+12+48=106\]
now 1 mole of sodium carbonate has 96 grams so 4 moles will have 4x106=424 oh yeah sry
oops sry now that means one mole of Na2CO3 will have 106 grams
thanks
To get the final answer, you need to convert to kg (:.
well that is easy enough... from here the question can b done by the asker himself yhe main question has been solved isnt it? even so the answer is .106 kg ok?
Well, zbay has already answered the question. It's .424kg of Na_2CO_3
yeah...
hah i again forgot to multiply by 4 wat a shame yeah k the answer is .424 kg i m really sry
Don't be sorry! We're all learning here.
Join our real-time social learning platform and learn together with your friends!