Question

2 Selected from the group at random but assume there are 5 males and 7 females.
1.) what is the probability that 2 females are selected?___________________
2)What is the probability that 2 males are selected?_______________________

Answer 1

1.\( \huge \frac{\binom{7}{2} }{\binom{12}{2}}\)

Answer 2

2.\( \huge \frac{\binom{5}{2} }{\binom{12}{2}} \)

Answer 3

do i multiply 7 by 2 and 12 by 2? for the 1st step

Answer 4

Of the 7 females, we select 2 and of the 5 males we select 0. C(7,2) times C(5,0) =21.

Of the 12 people, there are 66 possible random selections of 2.

Probability is the number of desirable outcomes (2 females) divided by the number of possible outcomes (66 groups of 2).

P(2 F) = 21/ 66 = 7/22 ==> ANS

Check this, CW.

Answer 5

)What is the probability that 2 males are selected.

Of the 7 females, we select 0. Of the 5 males, we select 2 for our two-person group.

C(7,0) times C(5,2) = 10 groups of 2-males

There are C(12,2) possible groups of 2 or 66 two person groups of any gender.

P(2M) = 10/66 = 5/33 ==> ANS

Answer 6

Check these, CW, and see if they are correct.

Answer 7

it is good for the second not the first

Answer 8

I was looking at the 3-dice problem. I'll look at this now.

Answer 9

Do you have P(2 F) = 21/ 66 for part (a) about the two females?

Answer 10

now i do:)