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• What is the sum of the geometric sequence 8, –16, 32 … if there are 15 terms
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8, -16, 32, -64, 128, -256, 512, -1024, 2048, -4096, 8192, -16384, 32768. -65536, 131072. 87384 is the sum.
\[Sum _{n}=\frac{a _{1}(1-r ^{n})}{1-r}\]
\[=\frac{8(1-(-2)^{15}}{1-(-2)}\]
87384
8(3)^15/3 = 24^15/3?
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No. Remember the rule...powers first
\[\frac{8(1-(-32768))}{3}\]
\[\frac{8(32769)}{3}\]
\[\frac{262152}{3}\]
\[87384\]
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ooh thank u so much
yw
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