Question

Solve the following system of equations.
2x – 3y + z = –1,,,,
3x + 2y + 2z = –1,,,,
x – y – 3z = –4

Answer 1

please help i dont know how to do this

Answer 2

add all of them,

2x-3y+z = -1
+
3x+2y+2z = -1
+
x-y-3z = -4
-------------------
6x-2y+0z = -6 ====>[1] (divide by 2)

3x-y = -3

y = 3x+3

Substitute in any two equations and you'll get the answer

Answer 3

2x-3y+z=-1...................1
3x-2y+2z=-1..................2
x=y+3z-4.........................3
sub 3 in 1,2

2(y+3z-4)-3y+z=-1..............1
3(y+3z-4)-2y+2z=-1.............2

2y+6z-8-3y+z=-1 then it -y+ 7z =7............1
3y+9z-12-2y+2z=-1 then it y+11z=-1...........2
let we take eq 2
y=-1-11z
sub this in eq 1
-(-1-11z)+7z=7..........1
1+11z+7z=7
18 z=6
z= 1/3
sub this in eq 2
y=-1-(11/3)=-4.666

sub y and z in eq 3
x=-4.666+(3/3)-4 =-7.666


you are welcome

Answer 4

so what is the answer

Answer 5

A.(–1, 0, 1)
B.(1, 2, 1)
C.(1, 1, 4)
D.(–1, –1, –2)

Answer 6

x=-7.6666 , y=-4.666 , z=1/3