Question

sqrtc-sqrtd/sqrtc+sqrtd

Answer 1

wtp?

Answer 2

lol satellite

Answer 3

u probably want to rationalize the denominator?

Answer 4

\[\frac{\sqrt{c}-\sqrt{d}}{\sqrt{c}+\sqrt{d}}\]

Answer 5

\[(\sqrt c-\sqrt d)/(\sqrt c+\sqrt d)=(\sqrt c-\sqrt d)(\sqrt c-\sqrt d)/(\sqrt c-\sqrt d)(\sqrt c+\sqrt d)\]

Answer 6

\[\frac{\sqrt{c}-\sqrt{d}}{\sqrt{c}+\sqrt{d}}\times \frac{\sqrt{c}-\sqrt{d}}{\sqrt{c}-\sqrt{d}}\]
\[\frac{\sqrt{c}-\sqrt{d})^2}{c-d}\]

Answer 7

therefore you have\[(\sqrt c-\sqrt d)^2 \over c-d\]

Answer 8

u missed a bracket satellite :P

Answer 9

what akshay said

Answer 10

all right wise gut
\[\frac{(\sqrt{c}-\sqrt{d})^2}{c-d}\]

Answer 11

therefore ur final answer is \[c - 2 \sqrt c \sqrt d + d \over c-d\]